By Feng Bao, Liqun Chen, Robert H. Deng, Guojun Wang
ISBN-10: 3319491504
ISBN-13: 9783319491509
ISBN-10: 3319491512
ISBN-13: 9783319491516
This e-book constitutes the court cases of the twelfth overseas convention on details safeguard and perform and adventure, ISPEC 2016, held in Zhangjiajie, China, in November 2016. The 25 papers awarded during this quantity have been conscientiously reviewed and chosen from seventy five submissions. They disguise a number of subject matters in info protection, from applied sciences to platforms and functions.
Read or Download Information Security Practice and Experience: 12th International Conference, ISPEC 2016, Zhangjiajie, China, November 16-18, 2016, Proceedings PDF
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Extra resources for Information Security Practice and Experience: 12th International Conference, ISPEC 2016, Zhangjiajie, China, November 16-18, 2016, Proceedings
Sample text
Let us first consider the following trivial cases when L = 2n , L = 0 and k ≥ 2n−1 before a full investigation on Ak (L) and Nk (L). When L = 2n , from Lemma 3, we have that for any k ≥ 1, Ak (2n ) = ∅, Nk (2n ) = 0. Because only all-zero sequence has 0 linear complexity and only all-one sequence has 1 linear complexity, we always have n Ak (0) = {S ∈ S 2 : wH (S) ≤ k}, k Nk (0) = j=0 and for k < 2n−1 we have 2n , j 18 W. Pan et al. Ak (1) = {S ∈ S 2n 2n n : wH (S) ≥ 2 − k}, Nk (1) = j=2n −k 2n j k = j=0 2n .
2iT −1 and d(U , U ) = 2iT (i1 > i2 > · · · > iT ), then we call U as a T -cube. ,2iT . We remark that a cube represents a subset of ZN with a special structure and “Cube” represents a class of subsets of ZN with the same structure. According to Lemma 1, we can easily know that the linear complexity of a cube with sides of length {2i1 , 2i2 , · · · , 2iT } is 2n − (2i1 + 2i2 + · · · + 2iT ). Example 1. Let set U = {1, 2, 5, 6, 18, 22, 49, 53}. As U = {1, 5, 49, 53} {2, 6, 18, 22} and {1, 5, 49, 53} = {1, 49} {5, 53}, {2, 6, 18, 22} = {2, 18} {6, 22}, then U is a cube with sides of length {16, 4, 1}.
However, we can not recover v, t and w directly, because that the length of the three vectors are longer than the basis vectors of the sublattice. Cryptanalysis of a Privacy Preserving Auditing for Data Integrity Protocol 43 To settle this problem, we introduce three pairs of plaintexts and ciphertexts (m1 , c1 ), (m2 , c2 ) and (m3 , c3 ). Note that it is easily to do this because the attacker know the public keys. Based on this observation, we know the ciphertexts (c1 , c2 , c3 ), the plaintexts (m1 , m2 , m3 ) and all the intermediate elements (v1 , v2 , v3 ), (n1 , n2 , n3 ) and (w1 , w2 , w3 ), which can be considered as the first three elements of the vectors defined above.
Information Security Practice and Experience: 12th International Conference, ISPEC 2016, Zhangjiajie, China, November 16-18, 2016, Proceedings by Feng Bao, Liqun Chen, Robert H. Deng, Guojun Wang
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