By L. A. A. Warnes (auth.)
ISBN-10: 0333580001
ISBN-13: 9780333580004
ISBN-10: 0333638034
ISBN-13: 9780333638033
ISBN-10: 1349137499
ISBN-13: 9781349137497
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Extra info for Solutions to Problems: Electronic and Electrical Engineering
Example text
08 w~ At 200 Hz the parallel branch is capacitive and we can make it resonate with the series inductance, L, at 200 Hz, when it will have minimum impedance. 27 0. 69 0. 3 mH. The attenuation is the ratio of IV0 /Vml at the two frequencies. t] Chapter two 32 Or, z. 0. 8 dB. 7 dB, practically the same. 20 The two T networks can be transformed to 1r form using admittances. 20 shows the circuit after these transformations. The other admittances are inconsequential. 2 If this is zero the input impedance will be infinite, that is when w2R2 CZ = 1 or w = 1/RC.
0. 15s) + 45s 2 Hence i ... 1 exp( -1 OOOt)]u(t) A. 362 mV. Q ! 5) 250, so A = [20 A - ;!!! 5t)]u(t) A. 553 A. 4b, the transformed circuit that can be solved. 06. 5 The output voltage in the s-domain is v = o x 2 000 2000 + 200000/ S v. = __s=-=-=m S + 100 5 X ---=-=~ s + 100 Chapter four 46 = 5(s + 100) - 500 = (s + 100) 2 5 s + 100 500 (s + 100? 677 V 6 When vin(t) = Vexp( -at) the transformed output voltage is vo - Vx s s+a s + 100 B s + 100 A(s + 100) + B(s + a) = Vs Hence and Thus A A = s+a + = aV/(a - 100) and B A + B = V (coeff.
We need to check that the coil, that is the 80mH inductance and series 50 resistance, has a high enough Q for this. 08 w~ At 200 Hz the parallel branch is capacitive and we can make it resonate with the series inductance, L, at 200 Hz, when it will have minimum impedance. 27 0. 69 0. 3 mH. The attenuation is the ratio of IV0 /Vml at the two frequencies. t] Chapter two 32 Or, z. 0. 8 dB. 7 dB, practically the same. 20 The two T networks can be transformed to 1r form using admittances. 20 shows the circuit after these transformations.
Solutions to Problems: Electronic and Electrical Engineering by L. A. A. Warnes (auth.)
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